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-rw-r--r--src/backend/optimizer/path/equivclass.c96
1 files changed, 19 insertions, 77 deletions
diff --git a/src/backend/optimizer/path/equivclass.c b/src/backend/optimizer/path/equivclass.c
index c115c2148db..5cdfec542cd 100644
--- a/src/backend/optimizer/path/equivclass.c
+++ b/src/backend/optimizer/path/equivclass.c
@@ -2035,7 +2035,7 @@ get_parent_relid(PlannerInfo *root, RelOptInfo *rel)
/*
* have_relevant_eclass_joinclause
* Detect whether there is an EquivalenceClass that could produce
- * a joinclause between the two given relations.
+ * a joinclause involving the two given relations.
*
* This is essentially a very cut-down version of
* generate_join_implied_equalities(). Note it's OK to occasionally say "yes"
@@ -2051,9 +2051,6 @@ have_relevant_eclass_joinclause(PlannerInfo *root,
foreach(lc1, root->eq_classes)
{
EquivalenceClass *ec = (EquivalenceClass *) lfirst(lc1);
- bool has_rel1;
- bool has_rel2;
- ListCell *lc2;
/*
* Won't generate joinclauses if single-member (this test covers the
@@ -2063,9 +2060,18 @@ have_relevant_eclass_joinclause(PlannerInfo *root,
continue;
/*
+ * We do not need to examine the individual members of the EC, because
+ * all that we care about is whether each rel overlaps the relids of
+ * at least one member, and a test on ec_relids is sufficient to prove
+ * that. (As with have_relevant_joinclause(), it is not necessary
+ * that the EC be able to form a joinclause relating exactly the two
+ * given rels, only that it be able to form a joinclause mentioning
+ * both, and this will surely be true if both of them overlap
+ * ec_relids.)
+ *
* Note we don't test ec_broken; if we did, we'd need a separate code
- * path to look through ec_sources. Checking the members anyway is OK
- * as a possibly-overoptimistic heuristic.
+ * path to look through ec_sources. Checking the membership anyway is
+ * OK as a possibly-overoptimistic heuristic.
*
* We don't test ec_has_const either, even though a const eclass won't
* generate real join clauses. This is because if we had "WHERE a.x =
@@ -2073,35 +2079,8 @@ have_relevant_eclass_joinclause(PlannerInfo *root,
* since the join result is likely to be small even though it'll end
* up being an unqualified nestloop.
*/
-
- /* Needn't scan if it couldn't contain members from each rel */
- if (!bms_overlap(rel1->relids, ec->ec_relids) ||
- !bms_overlap(rel2->relids, ec->ec_relids))
- continue;
-
- /* Scan the EC to see if it has member(s) in each rel */
- has_rel1 = has_rel2 = false;
- foreach(lc2, ec->ec_members)
- {
- EquivalenceMember *cur_em = (EquivalenceMember *) lfirst(lc2);
-
- if (cur_em->em_is_const || cur_em->em_is_child)
- continue; /* ignore consts and children here */
- if (bms_is_subset(cur_em->em_relids, rel1->relids))
- {
- has_rel1 = true;
- if (has_rel2)
- break;
- }
- if (bms_is_subset(cur_em->em_relids, rel2->relids))
- {
- has_rel2 = true;
- if (has_rel1)
- break;
- }
- }
-
- if (has_rel1 && has_rel2)
+ if (bms_overlap(rel1->relids, ec->ec_relids) &&
+ bms_overlap(rel2->relids, ec->ec_relids))
return true;
}
@@ -2112,7 +2091,7 @@ have_relevant_eclass_joinclause(PlannerInfo *root,
/*
* has_relevant_eclass_joinclause
* Detect whether there is an EquivalenceClass that could produce
- * a joinclause between the given relation and anything else.
+ * a joinclause involving the given relation and anything else.
*
* This is the same as have_relevant_eclass_joinclause with the other rel
* implicitly defined as "everything else in the query".
@@ -2125,9 +2104,6 @@ has_relevant_eclass_joinclause(PlannerInfo *root, RelOptInfo *rel1)
foreach(lc1, root->eq_classes)
{
EquivalenceClass *ec = (EquivalenceClass *) lfirst(lc1);
- bool has_rel1;
- bool has_rel2;
- ListCell *lc2;
/*
* Won't generate joinclauses if single-member (this test covers the
@@ -2137,45 +2113,11 @@ has_relevant_eclass_joinclause(PlannerInfo *root, RelOptInfo *rel1)
continue;
/*
- * Note we don't test ec_broken; if we did, we'd need a separate code
- * path to look through ec_sources. Checking the members anyway is OK
- * as a possibly-overoptimistic heuristic.
- *
- * We don't test ec_has_const either, even though a const eclass won't
- * generate real join clauses. This is because if we had "WHERE a.x =
- * b.y and a.x = 42", it is worth considering a join between a and b,
- * since the join result is likely to be small even though it'll end
- * up being an unqualified nestloop.
+ * Per the comment in have_relevant_eclass_joinclause, it's sufficient
+ * to find an EC that mentions both this rel and some other rel.
*/
-
- /* Needn't scan if it couldn't contain members from each rel */
- if (!bms_overlap(rel1->relids, ec->ec_relids) ||
- bms_is_subset(ec->ec_relids, rel1->relids))
- continue;
-
- /* Scan the EC to see if it has member(s) in each rel */
- has_rel1 = has_rel2 = false;
- foreach(lc2, ec->ec_members)
- {
- EquivalenceMember *cur_em = (EquivalenceMember *) lfirst(lc2);
-
- if (cur_em->em_is_const || cur_em->em_is_child)
- continue; /* ignore consts and children here */
- if (bms_is_subset(cur_em->em_relids, rel1->relids))
- {
- has_rel1 = true;
- if (has_rel2)
- break;
- }
- if (!bms_overlap(cur_em->em_relids, rel1->relids))
- {
- has_rel2 = true;
- if (has_rel1)
- break;
- }
- }
-
- if (has_rel1 && has_rel2)
+ if (bms_overlap(rel1->relids, ec->ec_relids) &&
+ !bms_is_subset(ec->ec_relids, rel1->relids))
return true;
}